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12490433 is a prime number
BaseRepresentation
bin101111101001…
…011011000001
3212111120122122
4233221123001
511144143213
61123414025
7211111154
oct57513301
925446578
1012490433
11706127a
124224315
1327842b7
141931c9b
15116ad08
hexbe96c1

12490433 has 2 divisors, whose sum is σ = 12490434. Its totient is φ = 12490432.

The previous prime is 12490417. The next prime is 12490447. The reversal of 12490433 is 33409421.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10608049 + 1882384 = 3257^2 + 1372^2 .

It is a cyclic number.

It is not a de Polignac number, because 12490433 - 24 = 12490417 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12490463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6245216 + 6245217.

It is an arithmetic number, because the mean of its divisors is an integer number (6245217).

Almost surely, 212490433 is an apocalyptic number.

It is an amenable number.

12490433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12490433 is an equidigital number, since it uses as much as digits as its factorization.

12490433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 26.

The square root of 12490433 is about 3534.1806688397. The cubic root of 12490433 is about 232.0202184619.

Adding to 12490433 its reverse (33409421), we get a palindrome (45899854).

The spelling of 12490433 in words is "twelve million, four hundred ninety thousand, four hundred thirty-three".