Base | Representation |
---|---|
bin | 1011010111001010100101… |
… | …0011101111101000010111 |
3 | 1122020021121011002100010112 |
4 | 2311302221103233220113 |
5 | 3114134323442001403 |
6 | 42323005041513235 |
7 | 2426363260012622 |
oct | 265625123575027 |
9 | 48207534070115 |
10 | 12492605422103 |
11 | 3a870a20964a4 |
12 | 149919834281b |
13 | 6c8080871081 |
14 | 312906ad2db9 |
15 | 169e647979d8 |
hex | b5ca94efa17 |
12492605422103 has 2 divisors, whose sum is σ = 12492605422104. Its totient is φ = 12492605422102.
The previous prime is 12492605422057. The next prime is 12492605422117. The reversal of 12492605422103 is 30122450629421.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12492605422103 - 214 = 12492605405719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12492605422153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6246302711051 + 6246302711052.
It is an arithmetic number, because the mean of its divisors is an integer number (6246302711052).
Almost surely, 212492605422103 is an apocalyptic number.
12492605422103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12492605422103 is an equidigital number, since it uses as much as digits as its factorization.
12492605422103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 207360, while the sum is 41.
Adding to 12492605422103 its sum of digits (41), we get a square (12492605422144 = 35344882).
The spelling of 12492605422103 in words is "twelve trillion, four hundred ninety-two billion, six hundred five million, four hundred twenty-two thousand, one hundred three".
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