Base | Representation |
---|---|
bin | 1011010111001011100011… |
… | …1110101000011101101111 |
3 | 1122020022021110210002121120 |
4 | 2311302320332220131233 |
5 | 3114140343242320213 |
6 | 42323051112432023 |
7 | 2426402631436233 |
oct | 265627076503557 |
9 | 48208243702546 |
10 | 12492868323183 |
11 | 3a87217530a16 |
12 | 14992503a8613 |
13 | 6c80c317c941 |
14 | 31292d9aa5c3 |
15 | 169e7c8c9423 |
hex | b5cb8fa876f |
12492868323183 has 4 divisors (see below), whose sum is σ = 16657157764248. Its totient is φ = 8328578882120.
The previous prime is 12492868323127. The next prime is 12492868323193. The reversal of 12492868323183 is 38132386829421.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12492868323183 - 217 = 12492868192111 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12492868323193) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2082144720528 + ... + 2082144720533.
It is an arithmetic number, because the mean of its divisors is an integer number (4164289441062).
Almost surely, 212492868323183 is an apocalyptic number.
12492868323183 is a deficient number, since it is larger than the sum of its proper divisors (4164289441065).
12492868323183 is an equidigital number, since it uses as much as digits as its factorization.
12492868323183 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4164289441064.
The product of its digits is 23887872, while the sum is 60.
The spelling of 12492868323183 in words is "twelve trillion, four hundred ninety-two billion, eight hundred sixty-eight million, three hundred twenty-three thousand, one hundred eighty-three".
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