1250000047 has 2 divisors, whose sum is σ = 1250000048. Its totient is φ = 1250000046.

The previous prime is 1250000041. The next prime is 1250000051. The reversal of 1250000047 is 7400000521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1250000047 - 2²⁷ = 1115782319 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1249999979 and 1250000033.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1250000041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625000023 + 625000024.

It is an arithmetic number, because the mean of its divisors is an integer number (625000024).

Almost surely, 2^1250000047 is an apocalyptic number.

1250000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1250000047 is an equidigital number, since it uses as much as digits as its factorization.

1250000047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 280, while the sum is 19.

The square root of 1250000047 is about 35355.3397240077. The cubic root of 1250000047 is about 1077.2173585171.

Adding to 1250000047 its reverse (7400000521), we get a palindrome (8650000568).

The spelling of 1250000047 in words is "one billion, two hundred fifty million, forty-seven", and thus it is an aban number.