Base | Representation |
---|---|
bin | 1011010111100110101010… |
… | …1010110110111110001001 |
3 | 1122021000001120002201012020 |
4 | 2311321222222312332021 |
5 | 3114300243434421330 |
6 | 42330253113235053 |
7 | 2430051142502226 |
oct | 265715252667611 |
9 | 48230046081166 |
10 | 12500144451465 |
11 | 3a8a310734880 |
12 | 149a741102a89 |
13 | 6c89b2745ba8 |
14 | 31302008494d |
15 | 16a256589210 |
hex | b5e6aab6f89 |
12500144451465 has 32 divisors (see below), whose sum is σ = 22325839405056. Its totient is φ = 5919730138560.
The previous prime is 12500144451451. The next prime is 12500144451493. The reversal of 12500144451465 is 56415444100521.
It is not a de Polignac number, because 12500144451465 - 25 = 12500144451433 is a prime.
It is a super-3 number, since 3×125001444514653 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 880905129 + ... + 880919318.
It is an arithmetic number, because the mean of its divisors is an integer number (697682481408).
Almost surely, 212500144451465 is an apocalyptic number.
12500144451465 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
12500144451465 is a deficient number, since it is larger than the sum of its proper divisors (9825694953591).
12500144451465 is a wasteful number, since it uses less digits than its factorization.
12500144451465 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1761824509.
The product of its (nonzero) digits is 384000, while the sum is 42.
Adding to 12500144451465 its reverse (56415444100521), we get a palindrome (68915588551986).
The spelling of 12500144451465 in words is "twelve trillion, five hundred billion, one hundred forty-four million, four hundred fifty-one thousand, four hundred sixty-five".
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