Base | Representation |
---|---|
bin | 10111010010001000… |
… | …10010111111101111 |
3 | 1012021011020112022211 |
4 | 23221010102333233 |
5 | 201100014333203 |
6 | 5424213351251 |
7 | 621523353502 |
oct | 135104227757 |
9 | 35234215284 |
10 | 12500152303 |
11 | 5335012491 |
12 | 250a338527 |
13 | 1242971032 |
14 | 868213139 |
15 | 4d2618c6d |
hex | 2e9112fef |
12500152303 has 2 divisors, whose sum is σ = 12500152304. Its totient is φ = 12500152302.
The previous prime is 12500152297. The next prime is 12500152333. The reversal of 12500152303 is 30325100521.
It is a weak prime.
It is an emirp because it is prime and its reverse (30325100521) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12500152303 is a prime.
It is a super-3 number, since 3×125001523033 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12500152333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6250076151 + 6250076152.
It is an arithmetic number, because the mean of its divisors is an integer number (6250076152).
Almost surely, 212500152303 is an apocalyptic number.
12500152303 is a deficient number, since it is larger than the sum of its proper divisors (1).
12500152303 is an equidigital number, since it uses as much as digits as its factorization.
12500152303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 22.
Adding to 12500152303 its reverse (30325100521), we get a palindrome (42825252824).
The spelling of 12500152303 in words is "twelve billion, five hundred million, one hundred fifty-two thousand, three hundred three".
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