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125002489 is a prime number
BaseRepresentation
bin1110111001101…
…10001011111001
322201012210011211
413130312023321
5224000034424
620223123121
73045334513
oct734661371
9281183154
10125002489
1164619247
1235a434a1
131cb88b91
141285cbb3
15ae92b94
hex77362f9

125002489 has 2 divisors, whose sum is σ = 125002490. Its totient is φ = 125002488.

The previous prime is 125002483. The next prime is 125002511. The reversal of 125002489 is 984200521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 123543225 + 1459264 = 11115^2 + 1208^2 .

It is a cyclic number.

It is not a de Polignac number, because 125002489 - 25 = 125002457 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 125002489.

It is not a weakly prime, because it can be changed into another prime (125002483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62501244 + 62501245.

It is an arithmetic number, because the mean of its divisors is an integer number (62501245).

Almost surely, 2125002489 is an apocalyptic number.

It is an amenable number.

125002489 is a deficient number, since it is larger than the sum of its proper divisors (1).

125002489 is an equidigital number, since it uses as much as digits as its factorization.

125002489 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 31.

The square root of 125002489 is about 11180.4511984088. The cubic root of 125002489 is about 500.0033186446.

The spelling of 125002489 in words is "one hundred twenty-five million, two thousand, four hundred eighty-nine".