Base | Representation |
---|---|
bin | 10010001100001100001… |
… | …101101110010010110011 |
3 | 11102111120110120011212222 |
4 | 102030030031232102303 |
5 | 130440040321012334 |
6 | 2354132144111255 |
7 | 156212111101052 |
oct | 22141415562263 |
9 | 4374513504788 |
10 | 1250040407219 |
11 | 44215924873a |
12 | 18232400552b |
13 | 90b55834716 |
14 | 44706376399 |
15 | 227b2db2d2e |
hex | 1230c36e4b3 |
1250040407219 has 2 divisors, whose sum is σ = 1250040407220. Its totient is φ = 1250040407218.
The previous prime is 1250040407207. The next prime is 1250040407221. The reversal of 1250040407219 is 9127040400521.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1250040407219 is a prime.
It is a super-2 number, since 2×12500404072192 (a number of 25 digits) contains 22 as substring.
Together with 1250040407221, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1250040407419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625020203609 + 625020203610.
It is an arithmetic number, because the mean of its divisors is an integer number (625020203610).
Almost surely, 21250040407219 is an apocalyptic number.
1250040407219 is a deficient number, since it is larger than the sum of its proper divisors (1).
1250040407219 is an equidigital number, since it uses as much as digits as its factorization.
1250040407219 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 35.
The spelling of 1250040407219 in words is "one trillion, two hundred fifty billion, forty million, four hundred seven thousand, two hundred nineteen".
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