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1250040407219 is a prime number
BaseRepresentation
bin10010001100001100001…
…101101110010010110011
311102111120110120011212222
4102030030031232102303
5130440040321012334
62354132144111255
7156212111101052
oct22141415562263
94374513504788
101250040407219
1144215924873a
1218232400552b
1390b55834716
1444706376399
15227b2db2d2e
hex1230c36e4b3

1250040407219 has 2 divisors, whose sum is σ = 1250040407220. Its totient is φ = 1250040407218.

The previous prime is 1250040407207. The next prime is 1250040407221. The reversal of 1250040407219 is 9127040400521.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1250040407219 is a prime.

It is a super-2 number, since 2×12500404072192 (a number of 25 digits) contains 22 as substring.

Together with 1250040407221, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1250040407419) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625020203609 + 625020203610.

It is an arithmetic number, because the mean of its divisors is an integer number (625020203610).

Almost surely, 21250040407219 is an apocalyptic number.

1250040407219 is a deficient number, since it is larger than the sum of its proper divisors (1).

1250040407219 is an equidigital number, since it uses as much as digits as its factorization.

1250040407219 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20160, while the sum is 35.

The spelling of 1250040407219 in words is "one trillion, two hundred fifty billion, forty million, four hundred seven thousand, two hundred nineteen".