Base | Representation |
---|---|
bin | 10010001100001100001… |
… | …101101111100101110011 |
3 | 11102111120110120110011201 |
4 | 102030030031233211303 |
5 | 130440040321200111 |
6 | 2354132144152031 |
7 | 156212111122411 |
oct | 22141415574563 |
9 | 4374513513151 |
10 | 1250040412531 |
11 | 442159251729 |
12 | 182324008617 |
13 | 90b55836c71 |
14 | 447063782b1 |
15 | 227b2db46c1 |
hex | 1230c36f973 |
1250040412531 has 2 divisors, whose sum is σ = 1250040412532. Its totient is φ = 1250040412530.
The previous prime is 1250040412529. The next prime is 1250040412547. The reversal of 1250040412531 is 1352140400521.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1250040412531 - 21 = 1250040412529 is a prime.
It is a super-2 number, since 2×12500404125312 (a number of 25 digits) contains 22 as substring.
Together with 1250040412529, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 1250040412531.
It is not a weakly prime, because it can be changed into another prime (1250040412561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625020206265 + 625020206266.
It is an arithmetic number, because the mean of its divisors is an integer number (625020206266).
Almost surely, 21250040412531 is an apocalyptic number.
1250040412531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1250040412531 is an equidigital number, since it uses as much as digits as its factorization.
1250040412531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4800, while the sum is 28.
The spelling of 1250040412531 in words is "one trillion, two hundred fifty billion, forty million, four hundred twelve thousand, five hundred thirty-one".
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