Base | Representation |
---|---|
bin | 111010001101101000… |
… | …1100111011001101101 |
3 | 102221200021111000200122 |
4 | 1310123101213121231 |
5 | 4022010440414003 |
6 | 133232441334325 |
7 | 12013622346203 |
oct | 1643321473155 |
9 | 387607430618 |
10 | 125011654253 |
11 | 49020902142 |
12 | 2028a1973a5 |
13 | ba33596765 |
14 | 609cb9d073 |
15 | 33b9e60238 |
hex | 1d1b46766d |
125011654253 has 2 divisors, whose sum is σ = 125011654254. Its totient is φ = 125011654252.
The previous prime is 125011654181. The next prime is 125011654319. The reversal of 125011654253 is 352456110521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76566763849 + 48444890404 = 276707^2 + 220102^2 .
It is a cyclic number.
It is not a de Polignac number, because 125011654253 - 210 = 125011653229 is a prime.
It is a super-2 number, since 2×1250116542532 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125011654753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62505827126 + 62505827127.
It is an arithmetic number, because the mean of its divisors is an integer number (62505827127).
Almost surely, 2125011654253 is an apocalyptic number.
It is an amenable number.
125011654253 is a deficient number, since it is larger than the sum of its proper divisors (1).
125011654253 is an equidigital number, since it uses as much as digits as its factorization.
125011654253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 125011654253 its reverse (352456110521), we get a palindrome (477467764774).
The spelling of 125011654253 in words is "one hundred twenty-five billion, eleven million, six hundred fifty-four thousand, two hundred fifty-three".
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