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12502476355121 is a prime number
BaseRepresentation
bin1011010111101111010110…
…1010010111011000110001
31122021020002001222200122022
42311323311222113120301
53114320032421330441
642331320334121225
72430163006401164
oct265736552273061
948236061880568
1012502476355121
113a902a7a66585
12149b092050215
136c8c948ab63c
143131a1a59adb
1516a34115d84b
hexb5ef5a97631

12502476355121 has 2 divisors, whose sum is σ = 12502476355122. Its totient is φ = 12502476355120.

The previous prime is 12502476355097. The next prime is 12502476355123. The reversal of 12502476355121 is 12155367420521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12024388464400 + 478087890721 = 3467620^2 + 691439^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12502476355121 is a prime.

Together with 12502476355123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12502476355123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6251238177560 + 6251238177561.

It is an arithmetic number, because the mean of its divisors is an integer number (6251238177561).

Almost surely, 212502476355121 is an apocalyptic number.

It is an amenable number.

12502476355121 is a deficient number, since it is larger than the sum of its proper divisors (1).

12502476355121 is an equidigital number, since it uses as much as digits as its factorization.

12502476355121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504000, while the sum is 44.

The spelling of 12502476355121 in words is "twelve trillion, five hundred two billion, four hundred seventy-six million, three hundred fifty-five thousand, one hundred twenty-one".