Base | Representation |
---|---|
bin | 10111010010011010… |
… | …11100100100010011 |
3 | 1012021022202101110011 |
4 | 23221031130210103 |
5 | 201101123111203 |
6 | 5424341015351 |
7 | 621552633301 |
oct | 135115344423 |
9 | 35238671404 |
10 | 12502550803 |
11 | 5336400516 |
12 | 250b0b4557 |
13 | 1243300972 |
14 | 868679271 |
15 | 4d293e76d |
hex | 2e935c913 |
12502550803 has 4 divisors (see below), whose sum is σ = 12505470120. Its totient is φ = 12499631488.
The previous prime is 12502550779. The next prime is 12502550807. The reversal of 12502550803 is 30805520521.
12502550803 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12502550803 - 217 = 12502419731 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12502550807) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1453225 + ... + 1461802.
It is an arithmetic number, because the mean of its divisors is an integer number (3126367530).
Almost surely, 212502550803 is an apocalyptic number.
12502550803 is a deficient number, since it is larger than the sum of its proper divisors (2919317).
12502550803 is an equidigital number, since it uses as much as digits as its factorization.
12502550803 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2919316.
The product of its (nonzero) digits is 12000, while the sum is 31.
The spelling of 12502550803 in words is "twelve billion, five hundred two million, five hundred fifty thousand, eight hundred three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •