Base | Representation |
---|---|
bin | 111010001110001101… |
… | …1100010000110100011 |
3 | 102221201121221110212110 |
4 | 1310130123202012203 |
5 | 4022030420444303 |
6 | 133234412530403 |
7 | 12014246141601 |
oct | 1643433420643 |
9 | 387647843773 |
10 | 125031031203 |
11 | 49030837351 |
12 | 20294780a03 |
13 | ba375bc400 |
14 | 60a15a4871 |
15 | 33bb9db703 |
hex | 1d1c6e21a3 |
125031031203 has 12 divisors (see below), whose sum is σ = 180518175960. Its totient is φ = 76942172736.
The previous prime is 125031031189. The next prime is 125031031207. The reversal of 125031031203 is 302130130521.
It is not a de Polignac number, because 125031031203 - 24 = 125031031187 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 125031031203.
It is not an unprimeable number, because it can be changed into a prime (125031031207) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 123304258 + ... + 123305271.
It is an arithmetic number, because the mean of its divisors is an integer number (15043181330).
Almost surely, 2125031031203 is an apocalyptic number.
125031031203 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
125031031203 is a deficient number, since it is larger than the sum of its proper divisors (55487144757).
125031031203 is a wasteful number, since it uses less digits than its factorization.
125031031203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 246609558 (or 246609545 counting only the distinct ones).
The product of its (nonzero) digits is 540, while the sum is 21.
Adding to 125031031203 its reverse (302130130521), we get a palindrome (427161161724).
The spelling of 125031031203 in words is "one hundred twenty-five billion, thirty-one million, thirty-one thousand, two hundred three".
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