1250320145047 has 2 divisors, whose sum is σ = 1250320145048. Its totient is φ = 1250320145046.

The previous prime is 1250320145033. The next prime is 1250320145083. The reversal of 1250320145047 is 7405410230521.

It is a weak prime.

It is an emirp because it is prime and its reverse (7405410230521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1250320145047 is a prime.

It is a super-2 number, since 2×1250320145047² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1250320145147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625160072523 + 625160072524.

It is an arithmetic number, because the mean of its divisors is an integer number (625160072524).

Almost surely, 2^{1250320145047} is an apocalyptic number.

1250320145047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1250320145047 is an equidigital number, since it uses as much as digits as its factorization.

1250320145047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 33600, while the sum is 34.

Adding to 1250320145047 its reverse (7405410230521), we get a palindrome (8655730375568).

The spelling of 1250320145047 in words is "one trillion, two hundred fifty billion, three hundred twenty million, one hundred forty-five thousand, forty-seven".