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125040511030050 = 2335271117935319037
BaseRepresentation
bin11100011011100101000011…
…001111100001001100100010
3121101201202102012112201022000
4130123211003033201030202
5112342130431310430200
61121534452345224430
735223610300053540
oct3433450317411442
9541652365481260
10125040511030050
113692942374a1a0
1212035832192116
1354a03673bac25
1422c3dc8c0ad90
15e6c8cd655300
hex71b9433e1322

125040511030050 has 768 divisors, whose sum is σ = 433222757683200. Its totient is φ = 25762743705600.

The previous prime is 125040511030049. The next prime is 125040511030079. The reversal of 125040511030050 is 50030115040521.

125040511030050 is a `hidden beast` number, since 1 + 2 + 504 + 0 + 5 + 1 + 103 + 0 + 0 + 50 = 666.

125040511030050 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 125040511029996 and 125040511030023.

It is an unprimeable number.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 6568279132 + ... + 6568298168.

It is an arithmetic number, because the mean of its divisors is an integer number (564092132400).

Almost surely, 2125040511030050 is an apocalyptic number.

125040511030050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 125040511030050, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (216611378841600).

125040511030050 is an abundant number, since it is smaller than the sum of its proper divisors (308182246653150).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

125040511030050 is a wasteful number, since it uses less digits than its factorization.

125040511030050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19608 (or 19597 counting only the distinct ones).

The product of its (nonzero) digits is 3000, while the sum is 27.

Adding to 125040511030050 its reverse (50030115040521), we get a palindrome (175070626070571).

The spelling of 125040511030050 in words is "one hundred twenty-five trillion, forty billion, five hundred eleven million, thirty thousand, fifty".