Base | Representation |
---|---|
bin | 1011010111110101011100… |
… | …1110001110010011101111 |
3 | 1122021101022010220020100022 |
4 | 2311331113032032103233 |
5 | 3114331410431120241 |
6 | 42332151004152355 |
7 | 2430251403026432 |
oct | 265752716162357 |
9 | 48241263806308 |
10 | 12504113145071 |
11 | 3a90a67986049 |
12 | 149b46a2386bb |
13 | 6c9195a25ac2 |
14 | 3132b91a9819 |
15 | 16a3d9bc854b |
hex | b5f5738e4ef |
12504113145071 has 2 divisors, whose sum is σ = 12504113145072. Its totient is φ = 12504113145070.
The previous prime is 12504113145011. The next prime is 12504113145193. The reversal of 12504113145071 is 17054131140521.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12504113145071 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12504113145011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6252056572535 + 6252056572536.
It is an arithmetic number, because the mean of its divisors is an integer number (6252056572536).
Almost surely, 212504113145071 is an apocalyptic number.
12504113145071 is a deficient number, since it is larger than the sum of its proper divisors (1).
12504113145071 is an equidigital number, since it uses as much as digits as its factorization.
12504113145071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16800, while the sum is 35.
Adding to 12504113145071 its reverse (17054131140521), we get a palindrome (29558244285592).
The spelling of 12504113145071 in words is "twelve trillion, five hundred four billion, one hundred thirteen million, one hundred forty-five thousand, seventy-one".
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