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125042134143 = 3371697966347
BaseRepresentation
bin111010001110100010…
…1111000110001111111
3102221202101211120020110
41310131011320301333
54022041241243033
6133235450521103
712014442413643
oct1643505706177
9387671746213
10125042134143
1149037030133
1220298436193
13ba399a8cb4
1460a2c54c23
1533bc981363
hex1d1d178c7f

125042134143 has 16 divisors (see below), whose sum is σ = 171241534080. Its totient is φ = 81102411936.

The previous prime is 125042134127. The next prime is 125042134163. The reversal of 125042134143 is 341431240521.

It is not a de Polignac number, because 125042134143 - 24 = 125042134127 is a prime.

It is a super-2 number, since 2×1250421341432 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 125042134143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125042134163) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1851496 + ... + 1917842.

It is an arithmetic number, because the mean of its divisors is an integer number (10702595880).

Almost surely, 2125042134143 is an apocalyptic number.

125042134143 is a deficient number, since it is larger than the sum of its proper divisors (46199399937).

125042134143 is a wasteful number, since it uses less digits than its factorization.

125042134143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 83366.

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 125042134143 its reverse (341431240521), we get a palindrome (466473374664).

The spelling of 125042134143 in words is "one hundred twenty-five billion, forty-two million, one hundred thirty-four thousand, one hundred forty-three".

Divisors: 1 3 37 111 16979 50937 66347 199041 628223 1884669 2454839 7364517 1126505713 3379517139 41680711381 125042134143