1250431101133 has 2 divisors, whose sum is σ = 1250431101134. Its totient is φ = 1250431101132.

The previous prime is 1250431101119. The next prime is 1250431101149. The reversal of 1250431101133 is 3311011340521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1240510343524 + 9920757609 = 1113782^2 + 99603^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1250431101133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1250431101098 and 1250431101107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1250431101163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625215550566 + 625215550567.

It is an arithmetic number, because the mean of its divisors is an integer number (625215550567).

Almost surely, 2^{1250431101133} is an apocalyptic number.

It is an amenable number.

1250431101133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1250431101133 is an equidigital number, since it uses as much as digits as its factorization.

1250431101133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 1250431101133 its reverse (3311011340521), we get a palindrome (4561442441654).

The spelling of 1250431101133 in words is "one trillion, two hundred fifty billion, four hundred thirty-one million, one hundred one thousand, one hundred thirty-three".