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125044132099 is a prime number
BaseRepresentation
bin111010001110100110…
…1100000100100000011
3102221202112121001220211
41310131031200210003
54022042244211344
6133240001414551
712014465404615
oct1643515404403
9387675531824
10125044132099
1149038175237
122029903a457
13ba3a228513
1460a3214db5
1533bcc28334
hex1d1d360903

125044132099 has 2 divisors, whose sum is σ = 125044132100. Its totient is φ = 125044132098.

The previous prime is 125044132097. The next prime is 125044132153. The reversal of 125044132099 is 990231440521.

It is a weak prime.

It is an emirp because it is prime and its reverse (990231440521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 125044132099 - 21 = 125044132097 is a prime.

Together with 125044132097, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (125044132097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62522066049 + 62522066050.

It is an arithmetic number, because the mean of its divisors is an integer number (62522066050).

Almost surely, 2125044132099 is an apocalyptic number.

125044132099 is a deficient number, since it is larger than the sum of its proper divisors (1).

125044132099 is an equidigital number, since it uses as much as digits as its factorization.

125044132099 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 77760, while the sum is 40.

The spelling of 125044132099 in words is "one hundred twenty-five billion, forty-four million, one hundred thirty-two thousand, ninety-nine".