125060426341 has 4 divisors (see below), whose sum is σ = 128110680684. Its totient is φ = 122010172000.

The previous prime is 125060426321. The next prime is 125060426347. The reversal of 125060426341 is 143624060521.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 143624060521 = 89 ⋅1613753489.

It can be written as a sum of positive squares in 2 ways, for example, as 25753509441 + 99306916900 = 160479^2 + 315130^2 .

It is a cyclic number.

It is not a de Polignac number, because 125060426341 - 2¹⁵ = 125060393573 is a prime.

It is a super-2 number, since 2×125060426341² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 125060426297 and 125060426306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125060426347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1525127110 + ... + 1525127191.

It is an arithmetic number, because the mean of its divisors is an integer number (32027670171).

Almost surely, 2^125060426341 is an apocalyptic number.

It is an amenable number.

125060426341 is a deficient number, since it is larger than the sum of its proper divisors (3050254343).

125060426341 is an equidigital number, since it uses as much as digits as its factorization.

125060426341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3050254342.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 125060426341 its reverse (143624060521), we get a palindrome (268684486862).

The spelling of 125060426341 in words is "one hundred twenty-five billion, sixty million, four hundred twenty-six thousand, three hundred forty-one".