Base | Representation |
---|---|
bin | 10111010011010100… |
… | …10011010101000011 |
3 | 1012021211222200202202 |
4 | 23221222103111003 |
5 | 201110042141024 |
6 | 5425211103415 |
7 | 622004136614 |
oct | 135152232503 |
9 | 35254880682 |
10 | 12510115139 |
11 | 533a6a7735 |
12 | 2511741b6b |
13 | 1244a4b9c2 |
14 | 869687c0b |
15 | 4d3435bae |
hex | 2e9a93543 |
12510115139 has 2 divisors, whose sum is σ = 12510115140. Its totient is φ = 12510115138.
The previous prime is 12510115097. The next prime is 12510115153. The reversal of 12510115139 is 93151101521.
12510115139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12510115139 is a prime.
It is not a weakly prime, because it can be changed into another prime (12510111139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6255057569 + 6255057570.
It is an arithmetic number, because the mean of its divisors is an integer number (6255057570).
Almost surely, 212510115139 is an apocalyptic number.
12510115139 is a deficient number, since it is larger than the sum of its proper divisors (1).
12510115139 is an equidigital number, since it uses as much as digits as its factorization.
12510115139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1350, while the sum is 29.
The spelling of 12510115139 in words is "twelve billion, five hundred ten million, one hundred fifteen thousand, one hundred thirty-nine".
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