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1251122014561 is a prime number
BaseRepresentation
bin10010001101001100101…
…011101110100101100001
311102121100211210112020011
4102031030223232211201
5130444244213431221
62354431342444521
7156250653441166
oct22151453564541
94377324715204
101251122014561
11442663840301
12182586293741
1390c98945773
14447a9c8806d
1522827d141e1
hex1234caee961

1251122014561 has 2 divisors, whose sum is σ = 1251122014562. Its totient is φ = 1251122014560.

The previous prime is 1251122014559. The next prime is 1251122014643. The reversal of 1251122014561 is 1654102211521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 763952913936 + 487169100625 = 874044^2 + 697975^2 .

It is an emirp because it is prime and its reverse (1654102211521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1251122014561 - 21 = 1251122014559 is a prime.

Together with 1251122014559, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1251122014531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625561007280 + 625561007281.

It is an arithmetic number, because the mean of its divisors is an integer number (625561007281).

Almost surely, 21251122014561 is an apocalyptic number.

It is an amenable number.

1251122014561 is a deficient number, since it is larger than the sum of its proper divisors (1).

1251122014561 is an equidigital number, since it uses as much as digits as its factorization.

1251122014561 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 31.

The spelling of 1251122014561 in words is "one trillion, two hundred fifty-one billion, one hundred twenty-two million, fourteen thousand, five hundred sixty-one".