Base | Representation |
---|---|
bin | 1011011000010000110000… |
… | …1111001100101101010100 |
3 | 1122022002020010011021221102 |
4 | 2312010030033030231110 |
5 | 3114441414412402202 |
6 | 42335402320205232 |
7 | 2430631162113263 |
oct | 266041417145524 |
9 | 48262203137842 |
10 | 12511445044052 |
11 | 3a9408a611299 |
12 | 14a0975769818 |
13 | 6c9a93a17c76 |
14 | 3137b2c405da |
15 | 16a6b8702d02 |
hex | b610c3ccb54 |
12511445044052 has 12 divisors (see below), whose sum is σ = 21905981832000. Its totient is φ = 6252593092056.
The previous prime is 12511445044031. The next prime is 12511445044069. The reversal of 12511445044052 is 25044054411521.
It is a super-3 number, since 3×125114450440523 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12511445043997 and 12511445044015.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 782348498 + ... + 782364489.
It is an arithmetic number, because the mean of its divisors is an integer number (1825498486000).
Almost surely, 212511445044052 is an apocalyptic number.
It is an amenable number.
12511445044052 is a deficient number, since it is larger than the sum of its proper divisors (9394536787948).
12511445044052 is a wasteful number, since it uses less digits than its factorization.
12511445044052 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1564714990 (or 1564714988 counting only the distinct ones).
The product of its (nonzero) digits is 128000, while the sum is 38.
Adding to 12511445044052 its reverse (25044054411521), we get a palindrome (37555499455573).
The spelling of 12511445044052 in words is "twelve trillion, five hundred eleven billion, four hundred forty-five million, forty-four thousand, fifty-two".
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