Base | Representation |
---|---|
bin | 111010010000111001… |
… | …1000111111000001001 |
3 | 102221221220102111211202 |
4 | 1310201303013320021 |
5 | 4022222000220241 |
6 | 133251351233545 |
7 | 12016421545646 |
oct | 1644163077011 |
9 | 387856374752 |
10 | 125121101321 |
11 | 49077666367 |
12 | 202ba9788b5 |
13 | ba50167238 |
14 | 60ad52cdcd |
15 | 33c487dd9b |
hex | 1d21cc7e09 |
125121101321 has 2 divisors, whose sum is σ = 125121101322. Its totient is φ = 125121101320.
The previous prime is 125121101233. The next prime is 125121101323. The reversal of 125121101321 is 123101121521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 124538410000 + 582691321 = 352900^2 + 24139^2 .
It is a cyclic number.
It is not a de Polignac number, because 125121101321 - 230 = 124047359497 is a prime.
Together with 125121101323, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 125121101293 and 125121101302.
It is not a weakly prime, because it can be changed into another prime (125121101323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62560550660 + 62560550661.
It is an arithmetic number, because the mean of its divisors is an integer number (62560550661).
Almost surely, 2125121101321 is an apocalyptic number.
It is an amenable number.
125121101321 is a deficient number, since it is larger than the sum of its proper divisors (1).
125121101321 is an equidigital number, since it uses as much as digits as its factorization.
125121101321 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 20.
Adding to 125121101321 its reverse (123101121521), we get a palindrome (248222222842).
The spelling of 125121101321 in words is "one hundred twenty-five billion, one hundred twenty-one million, one hundred one thousand, three hundred twenty-one".
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