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12512322113 is a prime number
BaseRepresentation
bin10111010011100101…
…01110001001000001
31012022000010211011112
423221302232021001
5201111123301423
65425330253105
7622031661134
oct135162561101
935260124145
1012512322113
115340974885
122512427195
1312453423c5
14869aa021b
154d371ea78
hex2e9cae241

12512322113 has 2 divisors, whose sum is σ = 12512322114. Its totient is φ = 12512322112.

The previous prime is 12512322101. The next prime is 12512322131. The reversal of 12512322113 is 31122321521.

Together with next prime (12512322131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12485157169 + 27164944 = 111737^2 + 5212^2 .

It is an emirp because it is prime and its reverse (31122321521) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12512322113 - 216 = 12512256577 is a prime.

It is not a weakly prime, because it can be changed into another prime (12512322143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256161056 + 6256161057.

It is an arithmetic number, because the mean of its divisors is an integer number (6256161057).

Almost surely, 212512322113 is an apocalyptic number.

It is an amenable number.

12512322113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12512322113 is an equidigital number, since it uses as much as digits as its factorization.

12512322113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 720, while the sum is 23.

Adding to 12512322113 its reverse (31122321521), we get a palindrome (43634643634).

The spelling of 12512322113 in words is "twelve billion, five hundred twelve million, three hundred twenty-two thousand, one hundred thirteen".