Base | Representation |
---|---|
bin | 11100011100110011110101… |
… | …111111110001101000011000 |
3 | 121102000211210100201101022110 |
4 | 130130303311333301220120 |
5 | 112400022213241401402 |
6 | 1122041403425152320 |
7 | 35232663656630550 |
oct | 3434636577615030 |
9 | 542024710641273 |
10 | 125125114403352 |
11 | 36961299091818 |
12 | 1204a10378b6a0 |
13 | 54a832b15156b |
14 | 22c81330c0160 |
15 | e6ebd0d3156c |
hex | 71ccf5ff1a18 |
125125114403352 has 384 divisors, whose sum is σ = 383632058557440. Its totient is φ = 33306311393280.
The previous prime is 125125114403299. The next prime is 125125114403447. The reversal of 125125114403352 is 253304411521521.
It is a super-2 number, since 2×1251251144033522 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 125125114403352.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1954040328 + ... + 1954104360.
It is an arithmetic number, because the mean of its divisors is an integer number (999041819160).
Almost surely, 2125125114403352 is an apocalyptic number.
125125114403352 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 125125114403352, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (191816029278720).
125125114403352 is an abundant number, since it is smaller than the sum of its proper divisors (258506944154088).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
125125114403352 is a wasteful number, since it uses less digits than its factorization.
125125114403352 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 64491 (or 64470 counting only the distinct ones).
The product of its (nonzero) digits is 144000, while the sum is 39.
Adding to 125125114403352 its reverse (253304411521521), we get a palindrome (378429525924873).
The spelling of 125125114403352 in words is "one hundred twenty-five trillion, one hundred twenty-five billion, one hundred fourteen million, four hundred three thousand, three hundred fifty-two".
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