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1251263887561 is a prime number
BaseRepresentation
bin10010001101010101001…
…000111011100011001001
311102121201201202102101201
4102031111020323203021
5131000042023400221
62354453411344201
7156254325362122
oct22152510734311
94377651672351
101251263887561
11442726931616
121826058b2061
1390cbc15a49c
14447c0a59049
15228354da891
hex1235523b8c9

1251263887561 has 2 divisors, whose sum is σ = 1251263887562. Its totient is φ = 1251263887560.

The previous prime is 1251263887493. The next prime is 1251263887589. The reversal of 1251263887561 is 1657883621521.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 963281397961 + 287982489600 = 981469^2 + 536640^2 .

It is a cyclic number.

It is not a de Polignac number, because 1251263887561 - 223 = 1251255498953 is a prime.

It is a super-2 number, since 2×12512638875612 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1251263887591) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625631943780 + 625631943781.

It is an arithmetic number, because the mean of its divisors is an integer number (625631943781).

Almost surely, 21251263887561 is an apocalyptic number.

It is an amenable number.

1251263887561 is a deficient number, since it is larger than the sum of its proper divisors (1).

1251263887561 is an equidigital number, since it uses as much as digits as its factorization.

1251263887561 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4838400, while the sum is 55.

The spelling of 1251263887561 in words is "one trillion, two hundred fifty-one billion, two hundred sixty-three million, eight hundred eighty-seven thousand, five hundred sixty-one".