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125130105433 = 136199187907
BaseRepresentation
bin111010010001001010…
…1011110001001011001
3102221222112100222011101
41310202111132021121
54022231301333213
6133252312231401
712016561230004
oct1644225361131
9387875328141
10125130105433
1149081756283
122030199b561
13ba51c9a708
1460b07d453b
1533c555bbdd
hex1d2255e259

125130105433 has 4 divisors (see below), whose sum is σ = 125139306960. Its totient is φ = 125120903908.

The previous prime is 125130105389. The next prime is 125130105469. The reversal of 125130105433 is 334501031521.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125130105433 is a prime.

It is a super-2 number, since 2×1251301054332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (125130106433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4580335 + ... + 4607572.

It is an arithmetic number, because the mean of its divisors is an integer number (31284826740).

Almost surely, 2125130105433 is an apocalyptic number.

It is an amenable number.

125130105433 is a deficient number, since it is larger than the sum of its proper divisors (9201527).

125130105433 is an equidigital number, since it uses as much as digits as its factorization.

125130105433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9201526.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 125130105433 its reverse (334501031521), we get a palindrome (459631136954).

The spelling of 125130105433 in words is "one hundred twenty-five billion, one hundred thirty million, one hundred five thousand, four hundred thirty-three".

Divisors: 1 13619 9187907 125130105433