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12513187568699 is a prime number
BaseRepresentation
bin1011011000010111010000…
…0110011001110000111011
31122022020201120000201101022
42312011310012121300323
53120004002004144244
642340251244413055
72431022311250126
oct266056406316073
948266646021338
1012513187568699
113a948a4189904
1214a118124718b
136c9cb0a3323c
143138da4353bd
1516a76b6a66ee
hexb6174199c3b

12513187568699 has 2 divisors, whose sum is σ = 12513187568700. Its totient is φ = 12513187568698.

The previous prime is 12513187568671. The next prime is 12513187568701. The reversal of 12513187568699 is 99686578131521.

12513187568699 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12513187568699 - 28 = 12513187568443 is a prime.

Together with 12513187568701, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12513187568639) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6256593784349 + 6256593784350.

It is an arithmetic number, because the mean of its divisors is an integer number (6256593784350).

Almost surely, 212513187568699 is an apocalyptic number.

12513187568699 is a deficient number, since it is larger than the sum of its proper divisors (1).

12513187568699 is an equidigital number, since it uses as much as digits as its factorization.

12513187568699 is an evil number, because the sum of its binary digits is even.

The product of its digits is 195955200, while the sum is 71.

The spelling of 12513187568699 in words is "twelve trillion, five hundred thirteen billion, one hundred eighty-seven million, five hundred sixty-eight thousand, six hundred ninety-nine".