Base | Representation |
---|---|
bin | 111010010001001111… |
… | …0101011101111101111 |
3 | 102221222200220122220202 |
4 | 1310202132223233233 |
5 | 4022232411123211 |
6 | 133252440104115 |
7 | 12016620605552 |
oct | 1644236535757 |
9 | 387880818822 |
10 | 125132520431 |
11 | 49083055746 |
12 | 2030276503b |
13 | ba526349c9 |
14 | 60b0c62699 |
15 | 33c588753b |
hex | 1d227abbef |
125132520431 has 2 divisors, whose sum is σ = 125132520432. Its totient is φ = 125132520430.
The previous prime is 125132520379. The next prime is 125132520437. The reversal of 125132520431 is 134025231521.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-125132520431 is a prime.
It is a super-2 number, since 2×1251325204312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 125132520394 and 125132520403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (125132520437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62566260215 + 62566260216.
It is an arithmetic number, because the mean of its divisors is an integer number (62566260216).
Almost surely, 2125132520431 is an apocalyptic number.
125132520431 is a deficient number, since it is larger than the sum of its proper divisors (1).
125132520431 is an equidigital number, since it uses as much as digits as its factorization.
125132520431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 125132520431 its reverse (134025231521), we get a palindrome (259157751952).
The spelling of 125132520431 in words is "one hundred twenty-five billion, one hundred thirty-two million, five hundred twenty thousand, four hundred thirty-one".
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