Base | Representation |
---|---|
bin | 1011011000010111100010… |
… | …1001000010010010000101 |
3 | 1122022020220212101110021210 |
4 | 2312011320221002102011 |
5 | 3120004131010201141 |
6 | 42340303005402033 |
7 | 2431024224654561 |
oct | 266057051022205 |
9 | 48266825343253 |
10 | 12513263756421 |
11 | 3a9493319686a |
12 | 14a11a2869319 |
13 | 6c9cc375a32c |
14 | 3139065c86a1 |
15 | 16a773205916 |
hex | b6178a42485 |
12513263756421 has 16 divisors (see below), whose sum is σ = 17666046169344. Its totient is φ = 7851343148544.
The previous prime is 12513263756419. The next prime is 12513263756423. The reversal of 12513263756421 is 12465736231521.
It is an interprime number because it is at equal distance from previous prime (12513263756419) and next prime (12513263756423).
It is not a de Polignac number, because 12513263756421 - 21 = 12513263756419 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12513263756423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1718980 + ... + 5289746.
It is an arithmetic number, because the mean of its divisors is an integer number (1104127885584).
Almost surely, 212513263756421 is an apocalyptic number.
It is an amenable number.
12513263756421 is a deficient number, since it is larger than the sum of its proper divisors (5152782412923).
12513263756421 is a wasteful number, since it uses less digits than its factorization.
12513263756421 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3639500.
The product of its digits is 1814400, while the sum is 48.
Adding to 12513263756421 its reverse (12465736231521), we get a palindrome (24978999987942).
The spelling of 12513263756421 in words is "twelve trillion, five hundred thirteen billion, two hundred sixty-three million, seven hundred fifty-six thousand, four hundred twenty-one".
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