125134022031 has 4 divisors (see below), whose sum is σ = 166845362712. Its totient is φ = 83422681352.

The previous prime is 125134022029. The next prime is 125134022063. The reversal of 125134022031 is 130220431521.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 125134022031 - 2¹ = 125134022029 is a prime.

It is a super-2 number, since 2×125134022031² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 125134021992 and 125134022010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (125134022231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20855670336 + ... + 20855670341.

It is an arithmetic number, because the mean of its divisors is an integer number (41711340678).

Almost surely, 2^125134022031 is an apocalyptic number.

125134022031 is a deficient number, since it is larger than the sum of its proper divisors (41711340681).

125134022031 is an equidigital number, since it uses as much as digits as its factorization.

125134022031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41711340680.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 125134022031 its reverse (130220431521), we get a palindrome (255354453552).

The spelling of 125134022031 in words is "one hundred twenty-five billion, one hundred thirty-four million, twenty-two thousand, thirty-one".