Base | Representation |
---|---|
bin | 111010010001010010… |
… | …0011100101001010001 |
3 | 102221222210202102122002 |
4 | 1310202210130221101 |
5 | 4022233303001231 |
6 | 133252532323345 |
7 | 12016636501046 |
oct | 1644244345121 |
9 | 387883672562 |
10 | 125134031441 |
11 | 49083997a11 |
12 | 20303173555 |
13 | ba52a436b3 |
14 | 60b11371cd |
15 | 33c5a850cb |
hex | 1d2291ca51 |
125134031441 has 2 divisors, whose sum is σ = 125134031442. Its totient is φ = 125134031440.
The previous prime is 125134031431. The next prime is 125134031453. The reversal of 125134031441 is 144130431521.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 63657308416 + 61476723025 = 252304^2 + 247945^2 .
It is an emirp because it is prime and its reverse (144130431521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 125134031441 - 26 = 125134031377 is a prime.
It is not a weakly prime, because it can be changed into another prime (125134031431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62567015720 + 62567015721.
It is an arithmetic number, because the mean of its divisors is an integer number (62567015721).
Almost surely, 2125134031441 is an apocalyptic number.
It is an amenable number.
125134031441 is a deficient number, since it is larger than the sum of its proper divisors (1).
125134031441 is an equidigital number, since it uses as much as digits as its factorization.
125134031441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5760, while the sum is 29.
Adding to 125134031441 its reverse (144130431521), we get a palindrome (269264462962).
The spelling of 125134031441 in words is "one hundred twenty-five billion, one hundred thirty-four million, thirty-one thousand, four hundred forty-one".
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