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125134031431 is a prime number
BaseRepresentation
bin111010010001010010…
…0011100101001000111
3102221222210202102121201
41310202210130221013
54022233303001211
6133252532323331
712016636501033
oct1644244345107
9387883672551
10125134031431
1149083997a02
1220303173547
13ba52a436a6
1460b11371c3
1533c5a850c1
hex1d2291ca47

125134031431 has 2 divisors, whose sum is σ = 125134031432. Its totient is φ = 125134031430.

The previous prime is 125134031389. The next prime is 125134031441. The reversal of 125134031431 is 134130431521.

It is a strong prime.

It is an emirp because it is prime and its reverse (134130431521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-125134031431 is a prime.

It is a super-2 number, since 2×1251340314312 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 125134031431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125134031441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62567015715 + 62567015716.

It is an arithmetic number, because the mean of its divisors is an integer number (62567015716).

Almost surely, 2125134031431 is an apocalyptic number.

125134031431 is a deficient number, since it is larger than the sum of its proper divisors (1).

125134031431 is an equidigital number, since it uses as much as digits as its factorization.

125134031431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 125134031431 its reverse (134130431521), we get a palindrome (259264462952).

The spelling of 125134031431 in words is "one hundred twenty-five billion, one hundred thirty-four million, thirty-one thousand, four hundred thirty-one".