1251343331333 has 2 divisors, whose sum is σ = 1251343331334. Its totient is φ = 1251343331332.

The previous prime is 1251343331311. The next prime is 1251343331347. The reversal of 1251343331333 is 3331333431521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1151172347329 + 100170984004 = 1072927^2 + 316498^2 .

It is a cyclic number.

It is not a de Polignac number, because 1251343331333 - 2²² = 1251339137029 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1251343331293 and 1251343331302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1251343331933) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625671665666 + 625671665667.

It is an arithmetic number, because the mean of its divisors is an integer number (625671665667).

Almost surely, 2^{1251343331333} is an apocalyptic number.

It is an amenable number.

1251343331333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1251343331333 is an equidigital number, since it uses as much as digits as its factorization.

1251343331333 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 87480, while the sum is 35.

Adding to 1251343331333 its reverse (3331333431521), we get a palindrome (4582676762854).

The spelling of 1251343331333 in words is "one trillion, two hundred fifty-one billion, three hundred forty-three million, three hundred thirty-one thousand, three hundred thirty-three".