Base | Representation |
---|---|
bin | 10010001101011010010… |
… | …001110110011110010101 |
3 | 11102121221202000002021222 |
4 | 102031122101312132111 |
5 | 131000231112042044 |
6 | 2354510131420125 |
7 | 156256423311554 |
oct | 22153221663625 |
9 | 4377852002258 |
10 | 1251350112149 |
11 | 442770574405 |
12 | 18262a754645 |
13 | 91003c89b57 |
14 | 447cc2a1d9b |
15 | 2283cd6d8ee |
hex | 1235a476795 |
1251350112149 has 2 divisors, whose sum is σ = 1251350112150. Its totient is φ = 1251350112148.
The previous prime is 1251350112109. The next prime is 1251350112179. The reversal of 1251350112149 is 9412110531521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 906957189649 + 344392922500 = 952343^2 + 586850^2 .
It is a cyclic number.
It is not a de Polignac number, because 1251350112149 - 240 = 151838484373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1251350112109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625675056074 + 625675056075.
It is an arithmetic number, because the mean of its divisors is an integer number (625675056075).
Almost surely, 21251350112149 is an apocalyptic number.
It is an amenable number.
1251350112149 is a deficient number, since it is larger than the sum of its proper divisors (1).
1251350112149 is an equidigital number, since it uses as much as digits as its factorization.
1251350112149 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10800, while the sum is 35.
The spelling of 1251350112149 in words is "one trillion, two hundred fifty-one billion, three hundred fifty million, one hundred twelve thousand, one hundred forty-nine".
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