Base | Representation |
---|---|
bin | 111010010001010100… |
… | …0100001100011010011 |
3 | 102221222212202201120121 |
4 | 1310202220201203103 |
5 | 4022234041200430 |
6 | 133253011251111 |
7 | 12016651541524 |
oct | 1644250414323 |
9 | 387885681517 |
10 | 125135100115 |
11 | 49084557913 |
12 | 203035a9a97 |
13 | ba53028c4c |
14 | 60b133484b |
15 | 33c5be6a7a |
hex | 1d22a218d3 |
125135100115 has 4 divisors (see below), whose sum is σ = 150162120144. Its totient is φ = 100108080088.
The previous prime is 125135100113. The next prime is 125135100161. The reversal of 125135100115 is 511001531521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 125135100115 - 21 = 125135100113 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 125135100115.
It is not an unprimeable number, because it can be changed into a prime (125135100113) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12513510007 + ... + 12513510016.
It is an arithmetic number, because the mean of its divisors is an integer number (37540530036).
Almost surely, 2125135100115 is an apocalyptic number.
125135100115 is a deficient number, since it is larger than the sum of its proper divisors (25027020029).
125135100115 is an equidigital number, since it uses as much as digits as its factorization.
125135100115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25027020028.
The product of its (nonzero) digits is 750, while the sum is 25.
Adding to 125135100115 its reverse (511001531521), we get a palindrome (636136631636).
The spelling of 125135100115 in words is "one hundred twenty-five billion, one hundred thirty-five million, one hundred thousand, one hundred fifteen".
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