Base | Representation |
---|---|
bin | 10010001101011110101… |
… | …000101100101010010101 |
3 | 11102122010211112211212201 |
4 | 102031132220230222111 |
5 | 131000403320211013 |
6 | 2354521302244501 |
7 | 156261301530325 |
oct | 22153650545225 |
9 | 4378124484781 |
10 | 1251423210133 |
11 | 4427a8860a68 |
12 | 18264b126731 |
13 | 910161717b5 |
14 | 447d7c8d285 |
15 | 228444ac3dd |
hex | 1235ea2ca95 |
1251423210133 has 2 divisors, whose sum is σ = 1251423210134. Its totient is φ = 1251423210132.
The previous prime is 1251423210073. The next prime is 1251423210157. The reversal of 1251423210133 is 3310123241521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1251371110609 + 52099524 = 1118647^2 + 7218^2 .
It is an emirp because it is prime and its reverse (3310123241521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1251423210133 - 217 = 1251423079061 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1251423210733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625711605066 + 625711605067.
It is an arithmetic number, because the mean of its divisors is an integer number (625711605067).
Almost surely, 21251423210133 is an apocalyptic number.
It is an amenable number.
1251423210133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1251423210133 is an equidigital number, since it uses as much as digits as its factorization.
1251423210133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 1251423210133 its reverse (3310123241521), we get a palindrome (4561546451654).
The spelling of 1251423210133 in words is "one trillion, two hundred fifty-one billion, four hundred twenty-three million, two hundred ten thousand, one hundred thirty-three".
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