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1251434131 is a prime number
BaseRepresentation
bin100101010010111…
…0101111010010011
310020012210102220021
41022211311322103
510030331343011
6324102324311
743004005003
oct11245657223
93205712807
101251434131
11592446a92
122ab129697
1316c36258c
14bc2bc003
1574cea471
hex4a975e93

1251434131 has 2 divisors, whose sum is σ = 1251434132. Its totient is φ = 1251434130.

The previous prime is 1251434113. The next prime is 1251434147. The reversal of 1251434131 is 1314341521.

Together with previous prime (1251434113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1251434131 - 29 = 1251433619 is a prime.

It is a super-2 number, since 2×12514341312 = 3132174768463450322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1251434096 and 1251434105.

It is not a weakly prime, because it can be changed into another prime (1251434111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625717065 + 625717066.

It is an arithmetic number, because the mean of its divisors is an integer number (625717066).

Almost surely, 21251434131 is an apocalyptic number.

1251434131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1251434131 is an equidigital number, since it uses as much as digits as its factorization.

1251434131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 25.

The square root of 1251434131 is about 35375.6149204505. The cubic root of 1251434131 is about 1077.6291531098.

Adding to 1251434131 its reverse (1314341521), we get a palindrome (2565775652).

The spelling of 1251434131 in words is "one billion, two hundred fifty-one million, four hundred thirty-four thousand, one hundred thirty-one".