125150325454307 has 2 divisors, whose sum is σ = 125150325454308. Its totient is φ = 125150325454306.

The previous prime is 125150325454291. The next prime is 125150325454309. The reversal of 125150325454307 is 703454523051521.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 125150325454307 - 2⁴ = 125150325454291 is a prime.

It is a super-2 number, since 2×125150325454307² (a number of 29 digits) contains 22 as substring.

Together with 125150325454309, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (125150325454309) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62575162727153 + 62575162727154.

It is an arithmetic number, because the mean of its divisors is an integer number (62575162727154).

Almost surely, 2^{125150325454307} is an apocalyptic number.

125150325454307 is a deficient number, since it is larger than the sum of its proper divisors (1).

125150325454307 is an equidigital number, since it uses as much as digits as its factorization.

125150325454307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520000, while the sum is 47.

The spelling of 125150325454307 in words is "one hundred twenty-five trillion, one hundred fifty billion, three hundred twenty-five million, four hundred fifty-four thousand, three hundred seven".