Base | Representation |
---|---|
bin | 1011011000011111001000… |
… | …0001001110010010101111 |
3 | 1122022110011210012110200111 |
4 | 2312013302001032102233 |
5 | 3120022313313441312 |
6 | 42341241032240451 |
7 | 2431125542643544 |
oct | 266076201162257 |
9 | 48273153173614 |
10 | 12515300140207 |
11 | 3a95788724077 |
12 | 14a1670840127 |
13 | 6ca259603257 |
14 | 313a5ac34bcb |
15 | 16a841da38a7 |
hex | b61f204e4af |
12515300140207 has 2 divisors, whose sum is σ = 12515300140208. Its totient is φ = 12515300140206.
The previous prime is 12515300140199. The next prime is 12515300140241. The reversal of 12515300140207 is 70204100351521.
12515300140207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12515300140207 - 23 = 12515300140199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12515300140807) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6257650070103 + 6257650070104.
It is an arithmetic number, because the mean of its divisors is an integer number (6257650070104).
Almost surely, 212515300140207 is an apocalyptic number.
12515300140207 is a deficient number, since it is larger than the sum of its proper divisors (1).
12515300140207 is an equidigital number, since it uses as much as digits as its factorization.
12515300140207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 31.
Adding to 12515300140207 its reverse (70204100351521), we get a palindrome (82719400491728).
The spelling of 12515300140207 in words is "twelve trillion, five hundred fifteen billion, three hundred million, one hundred forty thousand, two hundred seven".
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