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1251532215161 is a prime number
BaseRepresentation
bin10010001101100101001…
…000100001001101111001
311102122102102122212122222
4102031211020201031321
5131001114221341121
62354540154453425
7156264064206254
oct22154510411571
94378372585588
101251532215161
11442854343068
1218267b734275
1391032919007
144480854609b
152284dd400ab
hex12365221379

1251532215161 has 2 divisors, whose sum is σ = 1251532215162. Its totient is φ = 1251532215160.

The previous prime is 1251532215137. The next prime is 1251532215163. The reversal of 1251532215161 is 1615122351521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 827998083136 + 423534132025 = 909944^2 + 650795^2 .

It is a cyclic number.

It is not a de Polignac number, because 1251532215161 - 26 = 1251532215097 is a prime.

Together with 1251532215163, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1251532215163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 625766107580 + 625766107581.

It is an arithmetic number, because the mean of its divisors is an integer number (625766107581).

Almost surely, 21251532215161 is an apocalyptic number.

It is an amenable number.

1251532215161 is a deficient number, since it is larger than the sum of its proper divisors (1).

1251532215161 is an equidigital number, since it uses as much as digits as its factorization.

1251532215161 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18000, while the sum is 35.

Adding to 1251532215161 its reverse (1615122351521), we get a palindrome (2866654566682).

The spelling of 1251532215161 in words is "one trillion, two hundred fifty-one billion, five hundred thirty-two million, two hundred fifteen thousand, one hundred sixty-one".