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12517137152501 is a prime number
BaseRepresentation
bin1011011000100101111110…
…0000110111100111110101
31122022121220210212100210212
42312021133200313213311
53120040044102340001
642342143213555205
72431222220203532
oct266113740674765
948277823770725
1012517137152501
113a96540668653
1214a1aa3aa5b05
136ca490081c87
14313b92bc3d89
1516a8ed2bd7bb
hexb625f8379f5

12517137152501 has 2 divisors, whose sum is σ = 12517137152502. Its totient is φ = 12517137152500.

The previous prime is 12517137152489. The next prime is 12517137152521. The reversal of 12517137152501 is 10525173171521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7370709159025 + 5146427993476 = 2714905^2 + 2268574^2 .

It is a cyclic number.

It is not a de Polignac number, because 12517137152501 - 230 = 12516063410677 is a prime.

It is a super-4 number, since 4×125171371525014 (a number of 53 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12517137152521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6258568576250 + 6258568576251.

It is an arithmetic number, because the mean of its divisors is an integer number (6258568576251).

Almost surely, 212517137152501 is an apocalyptic number.

It is an amenable number.

12517137152501 is a deficient number, since it is larger than the sum of its proper divisors (1).

12517137152501 is an equidigital number, since it uses as much as digits as its factorization.

12517137152501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 73500, while the sum is 41.

The spelling of 12517137152501 in words is "twelve trillion, five hundred seventeen billion, one hundred thirty-seven million, one hundred fifty-two thousand, five hundred one".