Base | Representation |
---|---|
bin | 10111010100001110… |
… | …11010001110001111 |
3 | 1012022101100100201121 |
4 | 23222013122032033 |
5 | 201114020324201 |
6 | 5430042421411 |
7 | 622126036663 |
oct | 135207321617 |
9 | 35271310647 |
10 | 12517745551 |
11 | 5343a39563 |
12 | 2514201867 |
13 | 12464c0b3c |
14 | 86a6b28a3 |
15 | 4d3e419a1 |
hex | 2ea1da38f |
12517745551 has 4 divisors (see below), whose sum is σ = 12518291104. Its totient is φ = 12517200000.
The previous prime is 12517745549. The next prime is 12517745563. The reversal of 12517745551 is 15554771521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12517745551 - 21 = 12517745549 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 12517745498 and 12517745507.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12517145551) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236775 + ... + 284776.
It is an arithmetic number, because the mean of its divisors is an integer number (3129572776).
Almost surely, 212517745551 is an apocalyptic number.
12517745551 is a deficient number, since it is larger than the sum of its proper divisors (545553).
12517745551 is an equidigital number, since it uses as much as digits as its factorization.
12517745551 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 545552.
The product of its digits is 245000, while the sum is 43.
The spelling of 12517745551 in words is "twelve billion, five hundred seventeen million, seven hundred forty-five thousand, five hundred fifty-one".
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