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125204252142253 is a prime number
BaseRepresentation
bin11100011101111101100010…
…111110010010101010101101
3121102022102001121100001110011
4130131331202332102222231
5112402321302022023003
61122142012301413221
735241465041413444
oct3435754276225255
9542272047301404
10125204252142253
11369919092a2319
121206150a86a211
1354b29307442bb
1422cbcbd523d5b
15e71cb377a46d
hex71df62f92aad

125204252142253 has 2 divisors, whose sum is σ = 125204252142254. Its totient is φ = 125204252142252.

The previous prime is 125204252142241. The next prime is 125204252142311. The reversal of 125204252142253 is 352241252402521.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 68514390584964 + 56689861557289 = 8277342^2 + 7529267^2 .

It is a cyclic number.

It is not a de Polignac number, because 125204252142253 - 221 = 125204250045101 is a prime.

It is a super-2 number, since 2×1252042521422532 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125204252142653) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62602126071126 + 62602126071127.

It is an arithmetic number, because the mean of its divisors is an integer number (62602126071127).

Almost surely, 2125204252142253 is an apocalyptic number.

It is an amenable number.

125204252142253 is a deficient number, since it is larger than the sum of its proper divisors (1).

125204252142253 is an equidigital number, since it uses as much as digits as its factorization.

125204252142253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384000, while the sum is 40.

The spelling of 125204252142253 in words is "one hundred twenty-five trillion, two hundred four billion, two hundred fifty-two million, one hundred forty-two thousand, two hundred fifty-three".