Base | Representation |
---|---|
bin | 10010001110000100111… |
… | …001010101101000100111 |
3 | 11102200210120101120010011 |
4 | 102032010321111220213 |
5 | 131003212131401341 |
6 | 2355105112311051 |
7 | 156313224543244 |
oct | 22160471255047 |
9 | 4380716346104 |
10 | 1252065106471 |
11 | 442aa8125203 |
12 | 1827aa0a2487 |
13 | 910b914910a |
14 | 448592205cb |
15 | 22880a03b81 |
hex | 12384e55a27 |
1252065106471 has 4 divisors (see below), whose sum is σ = 1253210638312. Its totient is φ = 1250919574632.
The previous prime is 1252065106441. The next prime is 1252065106493. The reversal of 1252065106471 is 1746015602521.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1252065106471 - 29 = 1252065105959 is a prime.
It is a super-3 number, since 3×12520651064713 (a number of 37 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1252065106441) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 572764281 + ... + 572766466.
It is an arithmetic number, because the mean of its divisors is an integer number (313302659578).
Almost surely, 21252065106471 is an apocalyptic number.
1252065106471 is a deficient number, since it is larger than the sum of its proper divisors (1145531841).
1252065106471 is a wasteful number, since it uses less digits than its factorization.
1252065106471 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1145531840.
The product of its (nonzero) digits is 100800, while the sum is 40.
The spelling of 1252065106471 in words is "one trillion, two hundred fifty-two billion, sixty-five million, one hundred six thousand, four hundred seventy-one".
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