Base | Representation |
---|---|
bin | 10010001110000100111… |
… | …110011001111111000101 |
3 | 11102200210122220001112102 |
4 | 102032010332121333011 |
5 | 131003213001410023 |
6 | 2355105201001445 |
7 | 156313242045452 |
oct | 22160476317705 |
9 | 4380718801472 |
10 | 1252066435013 |
11 | 442aa8952379 |
12 | 1827aa623285 |
13 | 910b94c2a34 |
14 | 44859488829 |
15 | 22880bb7628 |
hex | 12384f99fc5 |
1252066435013 has 2 divisors, whose sum is σ = 1252066435014. Its totient is φ = 1252066435012.
The previous prime is 1252066434979. The next prime is 1252066435021. The reversal of 1252066435013 is 3105346602521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1200475218244 + 51591216769 = 1095662^2 + 227137^2 .
It is an emirp because it is prime and its reverse (3105346602521) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1252066435013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1252066435813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 626033217506 + 626033217507.
It is an arithmetic number, because the mean of its divisors is an integer number (626033217507).
Almost surely, 21252066435013 is an apocalyptic number.
It is an amenable number.
1252066435013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1252066435013 is an equidigital number, since it uses as much as digits as its factorization.
1252066435013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 38.
The spelling of 1252066435013 in words is "one trillion, two hundred fifty-two billion, sixty-six million, four hundred thirty-five thousand, thirteen".
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