Search a number
-
+
125211555014597 is a prime number
BaseRepresentation
bin11100011110000100010110…
…010000100010011111000101
3121102100002220112222101222122
4130132010112100202133011
5112402431231040431342
61122145221055335325
735242144025664452
oct3436042620423705
9542302815871878
10125211555014597
1136994a16602407
1212062a08521545
1354b352571253c
1422cc3b33a0829
15e7208e96e4d2
hex71e1164227c5

125211555014597 has 2 divisors, whose sum is σ = 125211555014598. Its totient is φ = 125211555014596.

The previous prime is 125211555014509. The next prime is 125211555014629. The reversal of 125211555014597 is 795410555112521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 112725233121796 + 12486321892801 = 10617214^2 + 3533599^2 .

It is a cyclic number.

It is not a de Polignac number, because 125211555014597 - 226 = 125211487905733 is a prime.

It is a super-2 number, since 2×1252115550145972 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (125211555074597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62605777507298 + 62605777507299.

It is an arithmetic number, because the mean of its divisors is an integer number (62605777507299).

Almost surely, 2125211555014597 is an apocalyptic number.

It is an amenable number.

125211555014597 is a deficient number, since it is larger than the sum of its proper divisors (1).

125211555014597 is an equidigital number, since it uses as much as digits as its factorization.

125211555014597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3150000, while the sum is 53.

The spelling of 125211555014597 in words is "one hundred twenty-five trillion, two hundred eleven billion, five hundred fifty-five million, fourteen thousand, five hundred ninety-seven".