Base | Representation |
---|---|
bin | 111010010011101001… |
… | …0010001010011000111 |
3 | 102222012022122012021000 |
4 | 1310213102101103013 |
5 | 4022414031334310 |
6 | 133304440224343 |
7 | 12021620143416 |
oct | 1644722212307 |
9 | 388168565230 |
10 | 125213152455 |
11 | 49114618786 |
12 | 2032576b0b3 |
13 | ba66256971 |
14 | 60bb85147d |
15 | 33cc9b34c0 |
hex | 1d274914c7 |
125213152455 has 32 divisors (see below), whose sum is σ = 222677913600. Its totient is φ = 66757322016.
The previous prime is 125213152447. The next prime is 125213152487. The reversal of 125213152455 is 554251312521.
125213152455 is a `hidden beast` number, since 1 + 2 + 52 + 1 + 3 + 152 + 455 = 666.
It is not a de Polignac number, because 125213152455 - 23 = 125213152447 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 236706 + ... + 553584.
It is an arithmetic number, because the mean of its divisors is an integer number (6958684800).
Almost surely, 2125213152455 is an apocalyptic number.
125213152455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
125213152455 is a deficient number, since it is larger than the sum of its proper divisors (97464761145).
125213152455 is a wasteful number, since it uses less digits than its factorization.
125213152455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 319820 (or 319814 counting only the distinct ones).
The product of its digits is 60000, while the sum is 36.
Adding to 125213152455 its reverse (554251312521), we get a palindrome (679464464976).
The spelling of 125213152455 in words is "one hundred twenty-five billion, two hundred thirteen million, one hundred fifty-two thousand, four hundred fifty-five".
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