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125213191217 is a prime number
BaseRepresentation
bin111010010011101001…
…0011010110000110001
3102222012022201011102122
41310213102122300301
54022414034104332
6133304441124025
712021620364422
oct1644722326061
9388168634378
10125213191217
1149114644914
1220325789615
13ba6626b4ba
1460bb861649
1533cc9bec12
hex1d2749ac31

125213191217 has 2 divisors, whose sum is σ = 125213191218. Its totient is φ = 125213191216.

The previous prime is 125213191189. The next prime is 125213191219. The reversal of 125213191217 is 712191312521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84472190881 + 40741000336 = 290641^2 + 201844^2 .

It is a cyclic number.

It is not a de Polignac number, because 125213191217 - 224 = 125196414001 is a prime.

Together with 125213191219, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (125213191219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 62606595608 + 62606595609.

It is an arithmetic number, because the mean of its divisors is an integer number (62606595609).

Almost surely, 2125213191217 is an apocalyptic number.

It is an amenable number.

125213191217 is a deficient number, since it is larger than the sum of its proper divisors (1).

125213191217 is an equidigital number, since it uses as much as digits as its factorization.

125213191217 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7560, while the sum is 35.

The spelling of 125213191217 in words is "one hundred twenty-five billion, two hundred thirteen million, one hundred ninety-one thousand, two hundred seventeen".